When dissolving calcium carbonate in excess of hydrochloric acid, 5.6 L of gas was released. The mass of calcium carbonate is
Compose a reaction equation
CaCO3 + 2HCl = CaCl2 + CO2 + H2O
Calculate the amount of gas substance (CO2) 5.6 L / 22.4 L / mol = 0.25 mol
Find the amount of calcium carbonate = 0.25 mol (equal to the amount of gas substance)
Calculate the mass of calcium carbonate (CaCO3) m = M * n (amount of substance) m = 0.25 mol * 100g / mol = 25 g
Remember: The process of learning a person lasts a lifetime. The value of the same knowledge for different people may be different, it is determined by their individual characteristics and needs. Therefore, knowledge is always needed at any age and position.