When dissolving calcium carbonate in excess of hydrochloric acid, 5.6 L of gas was released. The mass of calcium carbonate is

Compose a reaction equation
CaCO3 + 2HCl = CaCl2 + CO2 + H2O
Calculate the amount of gas substance (CO2) 5.6 L / 22.4 L / mol = 0.25 mol
Find the amount of calcium carbonate = 0.25 mol (equal to the amount of gas substance)
Calculate the mass of calcium carbonate (CaCO3) m = M * n (amount of substance) m = 0.25 mol * 100g / mol = 25 g

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