When dissolving sodium carbonate in excess of hydrochloric acid, 4.48 L of gas was released. The mass of sodium carbonate is
We make up the reaction equation
NaCO3 + 2HCl = 2NaCl + H2O + CO2
the number of moles of sodium carbonate = the number of moles of carbon dioxide = 4.48 / 22.4 = 0.2 mol
mass of sodium carbonate = 0.2 * 106 = 21.2 g.
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