When purifying copper sulfate, 150 mg of impurities were obtained, which amounted to 2% of the sample weight. Determine the mass of technical copper sulfate that has been purified.
Given: m (impurities) = 150 mg, ω (impurities) = 2%
Find: m (sample) -?
1. Calculate the mass of a sample of copper sulfate:
m (sample) = (m (impurities): ω (impurities)) • 100% = (150 mg: 2%) • 100% = 7500 mg = 7.5 g.
Answer: 7.5 g.
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