When the element is short-circuited, a current of 30 A occurs, and when an external resistance of 2 Ohms is connected

bystudin | August 4, 2020 | Education

When the element is short-circuited, a current of 30 A occurs, and when an external resistance of 2 Ohms is connected, a current of 5 A. Determine the EMF of the battery.

Ik = E / r
E = I * R + I * r
Ik * r = I * R + I * r
r = I * R / (Ik-I) = 2 * 5 / (30-2) = 0.35 Ohm

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