A 2K file is transferred over some connection at 256 bits per second. Determine the size of the file (in bytes) that can be transferred in the same time over another connection at 512 bits per second. Give one number in your answer – the file size in bytes.
Size of the transferred file = transfer time · transfer rate. Note that the transmission rate in the second case is 512/256 = 2 times the rate in the first case. Since the file transfer times are the same, the file size that can be transferred in the second case is also 2 times larger. It will be equal to 2 * 2 = 4KB = 4096 bytes.
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