An 8K file is transferred over some connection at 4096 bits per second. Determine the size of the file (in bytes) that can be transferred
September 14, 2020 | Education
| An 8K file is transferred over some connection at 4096 bits per second. Determine the size of the file (in bytes) that can be transferred in the same time over another connection at 256 bits per second.
Let’s define the transmission time:
8 KB / 4096 bits per second = (8 * 1024 * 8 bits) / (4 * 1024 bits per second) = 16 seconds.
Let’s calculate the file size:
16 seconds * 256 bits per second = 16 * 32 bytes = 512 bytes.
