Calculate the mass of lead obtained by reacting 6.5 g of zinc with an excess solution of lead nitrate

Pb (NO3) 2 + Zn = Zn (NO3) 2 + Pb
n (Zn) = 6.5 / 65 = 0.1 mol
The reaction equation shows that n (Zn) = n (Pb)
So n (Pb) = 0.1 mol
m (Pb) = 207g / mol * 0.1 mol = 20.7g
Write the number down to integers = 21

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