Calculate the mass of precipitate formed by the interaction of an excess of barium nitrate solution with a solution containing 7.84 g of sulfuric acid

We compose the reaction equations
Ba (NO3) 2 + H2SO4 = BaSO4 + 2HNO3
Calculate the amount of sulfuric acid substance n = 7.84 / 98 = 0.08 mol
According to the equation, calculate the amount of precipitate n (BaSO4) = 0.08 mol
m (BaSO4) = 18.64 g.
Write the number down to the tenth – 18.6

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