# Compare the period and frequency of oscillations of the mathematical pendulum at the equator and at the latitude of Moscow

May 27, 2020 | Education

| At equator more.

It all depends on the acceleration of gravity. At the latitude of Moscow, g = 9.82 m / s2, and at the equator g = 9.78 m / s2. We write the Thomson formula: T = 2 * п * √ (L / g), where L is the length of the thread, suspension. If we divide the periods of oscillation of the pendulum at the equator and at the latitude of Moscow, after the reductions it remains: T1 / T2 = √ (g2 / g1) = √ (9.82 m / s2 / 9.78 m / s2) = 1.004

And the frequency is inversely proportional to the period: v1 / v2 = T2 / T1 = 0.995

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