Determine how long the modem operating at a speed of 1200 bps will transmit information on a page of text from 40 lines of 80 characters per line
Given: K = 40 * 80 υ = 1200 bit / sec. Find: t-? Solution: 40 * 80 = 3200 characters. i = 1 byte, V = K * i = 3200 * 1 byte = 3200 bytes = 25600 bits. V = υ * t, t = V / υ = 25600 bit / 1200 bit / sec. = 21, (3) sec.
Answer: 21.4 sec.
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