Determine the approximate sidereal time at noon on September 23 in Cheboksary.

We assume that September 23 is the day of the autumnal equinox, and on the day of the spring equinox the sidereal time at noon is 0 hours. In addition, we take into account that the sidereal clock “runs away” by 4 minutes per day compared to the sun clock. For half a year the sidereal clock has gone 180 * forward 4 = 720 min. = 12 hours.

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