In mice, yellow color (A) dominates over black (a). What splitting by phenotype and genotype will be in F1 when two yellow

In mice, yellow color (A) dominates over black (a). What splitting by phenotype and genotype will be in F1 when two yellow mice are crossed, given that the A allele in the homozygous state causes embryo death?

Viable mice with yellow hair will be heterozygotes – Aa. They will produce germ cells of two types: a and A.
When crossing such mice with each other, we obtain offspring of the following type:
25% of mouse embryos conceived by this pair of individuals will be AA, which will cause their death;
50% of the mice will have a yellow coat color (Aa);
25% of the mice will have black coat (aa).
Answer: the splitting in the offspring of yellow mice will be 2: 1, both by genotype and phenotype.

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