In the first experiment, the bar moves uniformly on the table under the action of a horizontal force equal to 5 N.
August 28, 2020 | Education
| In the first experiment, the bar moves uniformly on the table under the action of a horizontal force equal to 5 N. In the second experiment, a horizontal force equal to 3 N is applied to the same bar at rest. In the third experiment, a horizontal force equal to 8 N is applied to the bar at rest. friction acting on the bar in each experiment?
1. Since the movement is uniform F = 5H
2. The maximum friction force at rest is equal to the sliding friction force. F = 3H.
3. The bar is the same, the static friction force is 3 N, a force of 8H was applied to the bar
F = 8Н – ЗН = 5Н
