On combustion of anoxic organic matter, 26.4 g of CO2, 5.4 g of H2O and 13.44 l of HCl are formed. This substance can be obtained

On combustion of anoxic organic matter, 26.4 g of CO2, 5.4 g of H2O and 13.44 l of HCl are formed. This substance can be obtained by reacting the corresponding hydrocarbon with an excess of HCl. Determine the molecular and structural formula of a substance

General formula of the substance CxHyClz
Let’s find the ratio of carbon, hydrogen and chlorine:
n (C) = n (CO2) = 26.4 / 44 = 0.6 mol
n (H) = n (H2O) * 2 + n (HCl) = (5.4 / 18) * 2 + 13.44 / 22.4 = 1.2 mol
n (Cl) = n (HCl) = 13.44 / 22.4 = 0.6 mol
The ratio of carbon to hydrogen and to chlorine is 1: 2: 1.
Given the method of obtaining the substance: the interaction of an oxygen-free hydrocarbon with an excess of HCl, we conclude that the compound belongs to alkenes, alkynes, arenes or alkadienes.
There is one possible option (based on the existing general formulas of the above classes of oxygen-free organic substances): C2H4Cl2 – dichloroethane

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