Protein is composed of 80 amino acids. Determine how many times the molecular weight of the region of the gene encoding this protein exceeds the molecular weight of the protein if the average molecular weight of an amino acid is 110, and a nucleotide is 300.
80 amino acids
M (amino acids) = 110 g / mol
M (nucleotide) = 300 g / mol
Let’s find the molecular weight of the protein, for this we multiply the number of amino acids by the average M (amino acids) = 110 x 80 = 8800 g / mol.
Now we find the number of nucleotides, there are three times more of them than amino acids, there are three times more of them than amino acids, that is, 80 x 3 = 240 pieces.
So we can find M (gene): 240 x 300 = 7200 g / mol.
We find the ratio of M (gene) and M (protein) = 72000/8800 = 8.2 times.
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