The length of the mathematical pendulum was increased 4 times. How has the period and frequency of its fluctuations changed?

The oscillation period of the mathematical pendulum is as follows:

T = 2 * pi * √ (l / g). Since l2 = 4 * l1, then T2 = T1 * √ (l2 / l1) = T1 * √ (4 * l1 / l1) = 2 * T1.

Since v = 1 / T, then v2 = 1 / T2 = 1 / (T1 * 2) = v1 / 2.
Answer: the period increased by 2 times, the frequency decreased by 2 times.

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