The resolution of the human eye at night is approximately 2 ‘. What will it be like when using a telescope with a lens diameter of 8 cm and a magnification of 200x?
The simplest action is 2 arc minutes (120 ″) divided by 200, we get 0.6 ″
Now let’s compare with the Rayleigh criterion (from the previous problem)
θ = 1.22 * λ / D = 1.22 * 0.5μm / (80000μm) = 0.0000076 rad = 1.6 ″
Since this is greater than 0.6 ″, the answer is Rayleigh’s diffraction constraint: 1.6 ″
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