What is the mass of iodine released during the interaction of 0.5 mol of potassium iodide with the required amount of chlorine?

We compose the reaction equation:
2KI + Cl2 = 2KCl + I2
Calculate the amount of iodine substance I2 = 0.25 mol (1/2 of the amount of substance KI)
Calculate the mass of iodine m (I2) = M * n (amount of substance) 254 g / mol * 0.25 mol = 63.5 g

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