What is the mass of the Earth if the angular velocity of the Moon is 13 °, 2 per day, and the average distance to it is 384,400 km?

Vl = 13.2˚day
R = 384400
Mz-?
decision
F = GmMz / R ^ 2
a = F / m = = GMz / R ^ 2
a = w ^ 2 ∙ R
P – 180˚
X – 13.2˚
X = (3.14 ∙ 13.2) / (180˚ ∙ 8640) = 2.665 * 10 ^ -6rad / s
Mz = (w ^ (2) R ^ 3) / G = = (384400000) ^ 3 * (2.665 ∙ 10 ^ (- 6)) ^ 2) / (6.67 ∙ 10 ^ (- 11)) = 6.04 ∙ 10 ^ 24

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