What volume of oxygen is formed upon decomposition of 0.6 mol of mercury (II) oxide?

Reaction equation:

2HgO = to => O2 ↑ + 2Hg

From the conditions of the problem, the amount of mercury oxide substance is:

n (HgO) = 0.6 mol

In the reaction equation, oxygen has a coefficient of 1, and mercury oxide has a coefficient of 2. It follows that the amount of a substance formed as a result of an oxygen reaction through an amount of a mercury oxide substance is expressed as follows:

n (O2) = n (HgO) ⋅ 1/2 = 0.6 ⋅ 1/2 = 0.3 mol,


V (O2) = Vm ⋅ n (O2) = 22.4 ⋅ 0, 3 = 6.72 L

Remember: The process of learning a person lasts a lifetime. The value of the same knowledge for different people may be different, it is determined by their individual characteristics and needs. Therefore, knowledge is always needed at any age and position.