What volume of oxygen is formed upon decomposition of 0.6 mol of mercury (II) oxide?

Reaction equation:

2HgO = to => O2 ↑ + 2Hg

From the conditions of the problem, the amount of mercury oxide substance is:

n (HgO) = 0.6 mol

In the reaction equation, oxygen has a coefficient of 1, and mercury oxide has a coefficient of 2. It follows that the amount of a substance formed as a result of an oxygen reaction through an amount of a mercury oxide substance is expressed as follows:

n (O2) = n (HgO) ⋅ 1/2 = 0.6 ⋅ 1/2 = 0.3 mol,

Hence:

V (O2) = Vm ⋅ n (O2) = 22.4 ⋅ 0, 3 = 6.72 L

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