With what linear speed is Petersburg (latitude 60 °) moving due to the rotation of the Earth around its own axis?

A point on the equator of the Earth, due to its daily rotation, moves at a speed of 0.5 km / s (2πRЗ / (24 • 3600)). The radius of the parallel at latitude φ is less than the radius of the equator by (cos φ) times. Thus, the length of the 60 ° parallel is 2 times less than the length of the equator. Consequently, the linear speed of St. Petersburg is 2 times less than the speed of a point on the equator, i.e. 0.25 km / s.

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